Solve for x, y and z, given the following equations: x + y + z = 6 2x - y + 3z = 9 -x + 2y + 2z = 9

We have to
solve for x, y and z using

x + y + z = 6 €¦ (1)

2x €“y +
3z = 9 €¦
(2)

-x + 2y + 2z = 9 €¦ (3)

Add (1) and

(3)

=> 3y + 3z = 15

=> y + z =
5

Substitute this in (1)

=> x + 5 =
6

=> x =
1

substitute this in
(2)

=> 2 €“ y + 3z = 9

=> 2 €“ (5
€“ z) + 3z = 9

=> 2 €“ 5 + z + 3z = 9

=> -3 + 4z = 9

=> 4z = 12

=> z
=
3

y + z = 5

=> y = 5 €“
3

=> y =
2

Therefore x
= 1, y = 2 and z =
3.