Find the indefinite integral `int x sqrt((2x-1)) dx` using integration by substitution `int x sqrt((2x-1)) dx` Substitute `u = 2x -1` Gives `x =...

`int x
sqrt((2x-1)) dx`

`u = 2x - 1`  (so `(du)/(dx) = 2`  not `2x`)

giving `x = (u+1)/2` ` and (dx)/(du) = 1/2`

Now we have

`int x sqrt((2x-1)) dx =...