Evaluate `int_1^18(3/z)^(1/2)dz`
`=int_1^18sqrt(3)z^(-1/2)dz`
`=sqrt(3)int_1^18z^(-1/2)dz`
Integrate the function.
`=sqrt(3)[z^(1/2)/(1/2)]=sqrt(3)[2z^(1/2)]`
Evaluate the function from 1 to 18.
`=sqrt(3)[2(18)^(1/2)-2(1)^(1/2)]`
=11.233
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