Solve the system: x+2y -z=3 2x-y+2z=8 x+y+z=3

x+2y
-z=3......(1)

2x-y+2z=8......(2)

x+y+z=
3......(3)

First we will add(3) and (2):

==> 3x +3z =

11........(4)

Now multiply (2) by 2 and then add to
(1):

==> 5x +3z = 19.....(5)

Now
subtract (4) from (5):

==> 2x = 8

==> x= 4

Substitute in (5) :

5(4) + 3z = 19

==>
3z=
-1

==> z=
-1/3

Now
substitute in (3):

4+ y -1/3 = 3

==> y=
-1+1/3

==> y= -2/3