30.0 mL of 0.10 M Ca(NO3)2 and 15.0 mL of 0.20 M Na3PO4 solutions are mixed. After the reaction is complete, which of these ions has the lowest...

Wednesday, April 3, 2019

Amount of
$\displaystyle{C}{a}{\left({N}{O}{3}\right)}_{{2}}$ mixed $\displaystyle={0.1}\times\frac{{30}}{{1000}}=$
0.003

Amount of $\displaystyle{N}{a}_{{3}}{P}{{O}_{{4}}^{{{3}-}}}$ mixed $\displaystyle=$
0.2xx15/1000 =
0.003

$\displaystyle{3}{C}{a}{\left({N}{O}_{{3}}\right)}_{{2}}+{2}{N}{a}_{{3}}{P}{O}_{{4}}\rightarrow$

Ca_3(PO_4)_2+6NaNO_3

$\displaystyle{C}{a}{\left({N}{O}_{{3}}\right)}_{{2}}:{2}{N}{a}_{{3}}{P}{O}_{{4}}=$
3:2 =
0.003:0.002

So 0.003 moles of
$\displaystyle{C}{a}{\left({N}{O}_{{3}}\right)}_{{2}}$ will react
with 0.002 moles...

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