30.0 mL of 0.10 M Ca(NO3)2 and 15.0 mL of 0.20 M Na3PO4 solutions are mixed. After the reaction is complete, which of these ions has the lowest...

Amount of
`Ca(NO3)_2` mixed `= 0.1xx30/1000 =
0.003`

Amount of `Na_3PO_4^(3-)` mixed`=
0.2xx15/1000 =
0.003 `

 

`3Ca(NO_3)_2+2Na_3PO_4 rarr

Ca_3(PO_4)_2+6NaNO_3`

 

`Ca(NO_3)_2:2Na_3PO_4 =
3:2 =
0.003:0.002`

 

So 0.003 moles of
`Ca(NO_3)_2` will react
with 0.002 moles...

• 
  

  />