If the equation y = 2x2 ˆ’ 5 + 3 x is graphed in the xy-plane, what is the value of its y-intercept?

This is a
linear equation which can be rewritten into the formula y=mx+b, where m is the slope and b is
the y-intercept.

I will assume that the first part of the equation is 2x2; in
many circumstances, this is written as 2*2 or 2(2) in order to ensure that the "x"
symbol is not confused for the variable "x."

The first step
according to order of operations is to multiply 2 and 2 in the first part of the equation. This
leaves you with y=4-5+3x. Combine the constants and one gets y=-1+3x.

The
final step is to put the terms in the correct order: y=3x-1. The final term is the y-intercept,
so in this case the y-intercept would be -1.

In order to show this on a
graph, go below the origin (point 0,0) and graph -1 on the y-axis. Go up three spaces and to the
right one space and place another point. Go up another three spaces and right one space and
place another point. Connect the points with a straight line. This is a simple way to graph a
line using slope-intercept form.