How many moles of Na+ ions are in 20 mL of 0.40 M Na3PO4?

Sunday, November 9, 2008

$\displaystyle{N}{a}_{{3}}{P}{O}_{{4}}$ will
ionized as follows in an aqueous solution.

$\displaystyle{N}{a}_{{3}}{P}{O}_{{4}}\rightarrow$
3Na^++PO_4^(3-)

As we can see from the balanced equation one $\displaystyle{N}{a}_{{3}}{P}{O}_{{4}}$ will
give us three $\displaystyle{N}{{a}}^{+}$ moles.

Amount of $\displaystyle{N}{a}_{{3}}{P}{O}_{{4}}=\frac{{0.4}}{{1000}}\times{20}=$
0.008mol

Mole ratio

$\displaystyle{N}{a}_{{3}}{P}{O}_{{4}}:{N}{{a}}^{+}=$
1:3

Amount of $\displaystyle{N}{{a}}^{+}$ $\displaystyle={0.008}\times{3}={0.024}{m}{o}{l}{s}$

So we have 0.024 moles of $\displaystyle{N}{{a}}^{+}$
ions.

Spooky Notes